2.3=0.5(10)t^2

Solution for 2.3=0.5(10)t^2 equation:

2.3=0.5(10)t^2

We move all terms to the left:

2.3-(0.5(10)t^2)=0

We get rid of parentheses

-0.510t^2+2.3=0

We add all the numbers together, and all the variables

-0.51t^2+2.3=0

a = -0.51; b = 0; c = +2.3;
Δ = b2-4ac
Δ = 02-4·(-0.51)·2.3
Δ = 4.692
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.692}}{2*-0.51}=\frac{0-\sqrt{4.692}}{-1.02}
=-\frac{\sqrt{}}{-1.02}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.692}}{2*-0.51}=\frac{0+\sqrt{4.692}}{-1.02}
=\frac{\sqrt{}}{-1.02}
$